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Revision as of 9:46:04, 16 February 2022 by JBFeast
Revision as of 9:50:24, 16 February 2022 by JBFeast
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Use a deck of cards. Cut for first. Players in turn draw cards  <br>
Use a deck of cards. Cut for first. Players in turn draw cards  <br>
until they have at least one numbered black and one numbered  <br>
until they have at least one numbered black and one numbered  <br>
red card. in other words a player will have one of one color and Lor more of the other color) Picture cards as drawn are placed face up in front of the player. . After all players have their hands players in turn play... a red and a black numbered card to indicate a square on the beard as & los are wild in their color if the player plays an empty space he places his initials in it, it he plays a space owned by an opponent he must pay rent The rent is determined by counting the number of spaces the .
red card. (In other words a player will have one of one color   <br>
Player owns in the n orthogonally connected group to which... the space belongs. This is multiplied by a factori determined by the suit of the played cards. The factor is worked out by assigning a value of 1 to the minor suits & & & and a value of Z to the maior suits Multiply the values of the two cards... (thus & f gives a factor of t'i and 4 & ♡ gives a factor of of 4.) If a player plays in his own space he puts a circle in it... If he chooses to, on is forced to play in a space a second time he looses the space and erases his initial and the circle... The space can now be claimed in the usual manner.
and 1 or more of the other color.) Picture cards as drawn are   <br>
placed face up in front of the player.   <br>
After all players have their hands, players in turn play <br>
a red and a black numbered card to indicate a square on the   <br>
board 9's & 10's are wild in their color. If the player plays   <br>
an empty space he places his initials in it. If he plays   <br>
a space owned by an opponent he must pay rent. The   <br>
rent is determined by counting the number of spaces the <br>
player owns in the orthogonally connected group to which <br>
the space belongs. This is multiplied by a factor determined by   <br>
the suit of the played cards. The factor is worked out by   <br>
assigning a value of 1 to the minor suits & & & and a value of Z to the maior suits Multiply the values of the two cards... (thus & f gives a factor of t'i and 4 & ♡ gives a factor of of 4.) If a player plays in his own space he puts a circle in it... If he chooses to, on is forced to play in a space a second time he looses the space and erases his initial and the circle... The space can now be claimed in the usual manner.
After playing the player draws from the deck until he again. has at least one numbered red a black card, when exhausted the used cards are the shuttled and reused.
After playing the player draws from the deck until he again. has at least one numbered red a black card, when exhausted the used cards are the shuttled and reused.
when a player plays on another players space he may after paying veut buy the space . Picture cards are used for busing... A zack is worth i, a queen 2, aking 3, The bayer pays the owner
when a player plays on another players space he may after paying veut buy the space . Picture cards are used for busing... A zack is worth i, a queen 2, aking 3, The bayer pays the owner
Pont for each orthogonally connected space in the group... If he has to use a value too high he does not receive change. The original owner gets the picture cards and a can then
Pont for each orthogonally connected space in the group... If he has to use a value too high he does not receive change. The original owner gets the picture cards and a can then
(cont, on 9/20)
(cont, on 9/20)